Addition Strategies Within 20 | 1st Grade Math
Addition Strategies Within 20
Learn useful addition strategies within 20 by counting on, starting with the larger addend, and making a ten. Choose a strategy that fits the numbers and makes addition easier.
This first grade addition lesson uses number lines, ten-frames, visual models, and decomposing numbers to help students solve addition facts within 20 with understanding and confidence.
๐ฏ What You Will Learn
Start with a number and count forward to add a small amount.
Switch the addends when that makes the counting easier.
Break apart one addend so the other addend can reach 10.
Use the method that is clear and efficient for the numbers in the problem.
๐ง Key Vocabulary
๐ ️ Three Useful Addition Moves
Start with the larger addend and count forward a small number of steps.
Break apart one addend so the other addend can reach 10.
If it helps, put the larger addend first. The sum stays the same.
๐ฃ Strategy 1: Count On
Counting on is useful when one addend is small. For 6 + 3, start at 6 and count forward three numbers: 7, 8, 9.
๐ Strategy 2: Start with the Larger Addend
For 2 + 8, it is easier to think 8 + 2. Start at 8 and count on two numbers: 9, 10. The order of the addends can change without changing the sum.
๐ Strategy 3: Make a Ten
Making 10 is especially helpful when an addend is close to 10. To solve 8 + 5, move 2 from the group of 5 to join the 8. That makes 10, with 3 left: 8 + 5 = 8 + 2 + 3 = 10 + 3 = 13.
๐ 25 Worked Examples
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Start at 5 and count on two numbers: 6, 7. Answer: 5 + 2 = 7.
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Start at 6 and count on three numbers: 7, 8, 9. Answer: 6 + 3 = 9.
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It is easier to start at 8 and count on 2: 9, 10. The order can be switched without changing the sum. Answer: 2 + 8 = 10.
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Because 2 is small, count on from 7: 8, 9. Answer: 7 + 2 = 9.
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9 needs 1 more to make 10. Break 4 into 1 and 3. Then 9 + 1 = 10, and 10 + 3 = 13. Answer: 9 + 4 = 13.
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8 needs 2 more to make 10. Break 5 into 2 and 3. Then 8 + 2 = 10, and 10 + 3 = 13. Answer: 8 + 5 = 13.
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7 needs 3 more to make 10. Break 5 into 3 and 2. Then 7 + 3 = 10, and 10 + 2 = 12. Answer: 7 + 5 = 12.
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6 needs 4 more to make 10. Break 7 into 4 and 3. Then 6 + 4 = 10, and 10 + 3 = 13. Answer: 6 + 7 = 13.
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9 needs 1 more to make 10. Break 6 into 1 and 5. Then 9 + 1 = 10, and 10 + 5 = 15. Answer: 9 + 6 = 15.
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8 needs 2 more to make 10. Break 7 into 2 and 5. Then 8 + 2 = 10, and 10 + 5 = 15. Answer: 8 + 7 = 15.
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Switch the order to think 9 + 4. Break 4 into 1 and 3. Then 9 + 1 + 3 = 10 + 3 = 13. Answer: 4 + 9 = 13.
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Start with 8. You can count on 3: 9, 10, 11. Answer: 3 + 8 = 11.
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Switch the order: 9 + 5. Break 5 into 1 and 4. Then 9 + 1 + 4 = 10 + 4 = 14. Answer: 5 + 9 = 14.
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Think 8 + 6. Eight needs 2 to make 10, so break 6 into 2 and 4. Then 8 + 2 + 4 = 10 + 4 = 14. Answer: 6 + 8 = 14.
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Think 8 + 7. Eight needs 2, so break 7 into 2 and 5. Then 8 + 2 + 5 = 10 + 5 = 15. Answer: 7 + 8 = 15.
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9 needs 1 more to make 10. Break 8 into 1 and 7. Then 9 + 1 = 10, and 10 + 7 = 17. Answer: 9 + 8 = 17.
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8 needs 2 more to make 10. Break 6 into 2 and 4. Then 8 + 2 = 10, and 10 + 4 = 14. Answer: 8 + 6 = 14.
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Switch the order to 9 + 7. Break 7 into 1 and 6. Then 9 + 1 + 6 = 10 + 6 = 16. Answer: 7 + 9 = 16.
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Count on is especially efficient because only two steps are needed: 7, 8. Answer: count on; 6 + 2 = 8.
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Make a ten is useful because 9 needs only 1 more to become 10. Break 5 into 1 and 4: 9 + 1 + 4 = 10 + 4 = 14. Answer: make a ten; 9 + 5 = 14.
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Eight needs 2 to make 10. Break 5 into 2 and 3. Answer: 5 = 2 + 3.
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The student added an extra 2 instead of taking that 2 from the 6, so the total changed. Split 6 into 2 and 4: 8 + 6 = 8 + 2 + 4 = 10 + 4 = 14. Correct answer: 8 + 6 = 14.
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Counting on 3 is simpler here: 7, 8, 9. Good mathematicians choose a strategy that fits the numbers. Answer: count on; 6 + 3 = 9.
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Changing the order of the addends does not change the sum. Starting with 9 makes counting on or making 10 easier. Answer: both sums equal 12.
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Eight needs 2 to make 10. Break 9 into 2 and 7. Then 8 + 2 + 7 = 10 + 7 = 17. Answer: 8 + 9 = 17.
๐ฎ Independent Practice — 30 Problems
- Find the sum: 4 + 2.
- Find the sum: 5 + 3.
- Find the sum: 7 + 2.
- Find the sum: 8 + 3.
- Find the sum: 9 + 2.
- Use a make-10 strategy: 9 + 4.
- Use a make-10 strategy: 8 + 5.
- Use a make-10 strategy: 7 + 5.
- Use a make-10 strategy: 6 + 7.
- Use a make-10 strategy: 9 + 6.
- Use a make-10 strategy: 8 + 7.
- Use a make-10 strategy: 7 + 8.
- Use a make-10 strategy: 9 + 8.
- Use a make-10 strategy: 6 + 9.
- Use a make-10 strategy: 5 + 8.
- Start with the larger addend to solve 2 + 9.
- Start with the larger addend to solve 3 + 8.
- Start with the larger addend to solve 4 + 9.
- Start with the larger addend to solve 2 + 7.
- Start with the larger addend to solve 3 + 9.
- Complete the make-10 step: 8 + 5 = 8 + 2 + □.
- Complete the make-10 step: 9 + 6 = 9 + 1 + □.
- Complete the make-10 step: 7 + 5 = 7 + 3 + □.
- Complete the make-10 step: 6 + 8 = 6 + 4 + □.
- True or false: 9 + 7 = 16.
- Which split helps solve 8 + 5 by making 10: 5 = 2 + 3 or 5 = 1 + 4?
- How many should be moved from the 4 in 9 + 4 to make 10 with 9?
- In 7 + 6, how many from the 6 are used to make 10 with 7?
- Explain in one sentence why switching 3 + 9 to 9 + 3 can help.
- Challenge: Find 8 + 9 using a make-10 strategy.
๐ Lesson Test — 15 Questions
- Find the sum: 4 + 3.
- Find the sum: 7 + 3.
- Use a make-10 strategy to find 8 + 4.
- Use a make-10 strategy to find 9 + 3.
- Use a make-10 strategy to find 7 + 6.
- Find 8 + 9.
- Start with the larger addend to solve 2 + 8.
- Complete: 9 + 5 = 9 + 1 + □.
- Complete: 8 + 7 = 8 + 2 + □.
- To solve 7 + 5 by making 10, how can 5 be split?
- True or false: 8 + 5 = 13.
- Fix the mistake: 9 + 4 = 9 + 1 + 4 = 14.
- Which strategy is especially efficient for 7 + 1: count on or make a ten? Find the sum too.
- What strategy breaks apart an addend so another addend can reach 10 before adding the leftover part?
- Challenge: Find 6 + 9 and show a make-10 step.
๐ Complete Answer Key
๐ Show practice answer key
Practice Answers
๐ Show test answer key
Test Answers
๐ก Common Mistakes to Watch For
This can work, but starting with one addend and counting on is often more efficient.
Break an addend apart; do not create new counters.
After making 10, add the part that remains.
A good strategy depends on the numbers. Counting on may be easier for +1, +2, or +3; making 10 may be easier near 10.
๐ Related Lessons
Review the partners of 10 before using make-10 addition strategies. Lesson 6 — Understanding Addition Within 10
Review what addition means with counters, pictures, and ten-frames.
๐จ️ Printable Companion
A free Addition Strategies Within 20 Practice Pack will be connected here as the MathLattice printable library grows. It will include count-on practice, make-10 models, ten-frames, strategy choice, error analysis, mixed practice, and an answer key.
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